A
Simulator for a Second Order, Closed Loop System
This page takes you to a simulator for a second order system being controlled
by a proportional controller. By
clicking
here, you can get the simulator. It will allow you to simulate
the system below.

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In the simulator, we assume
that the plant is a second order system.
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The plant is assumed to
have a damping ratio, z
and an undamped natural frequency, wn.
You can set those parameters in the simulator. That means that the
system is dynamic, and that the system dynamics will affect the performance
of the entire closed loop system.
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For steady state operation,
the output is proportional to the control effort (control signal) entering
the actuator. That constant is called K.
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In the simulator, the
following items can be set.
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K - The DC gain for G(s)
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In other words, it is
the ratio of the steady state output to the steady state input, assuming
a constant input, or an input that becomes constant after some time.
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wn
- The undamped natural frequency for G(s)
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z
- The damping ratio for G(s)
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Kp -
The proportional gain in the controller.
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The Input.
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The input is a constant,
but you can set the value.
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To operate the simulator,
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Enter the parameters as
listed above.
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Click the Start button.
A plot will be generated.
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Use Alt+PrintScreen to
put a copy of the plot picture on the clipboard after highlighting the
plot window.
Problems
Here are some problems to help you understand the operation of proportional
control to control second order systems.
P1
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First, predict the steady
state for these conditions.
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K = 2
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Kp =
5
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z
= 2.0
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wn
= 0.1
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Desired Output = 2.0
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Run the simulator and
determine the steady state for those conditions.
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Compare the theoretical
and simulated steady state value.
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Determine the amount of
overshoot in the closed loop system response.
P2
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Now, re-do Problem
P1 but change the value of the proportional
gain to the value below.
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Run the simulator and
determine the steady state for those conditions.
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Compare the theoretical
and simulated steady state value.
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Determine the amount of
overshoot in the closed loop system response. In addition, compare
the overshoot in this problem with the overshoot for Problem
P1.