Why Are Capacitors Important?What Is A Capacitor?Voltage Current Relationships In CapacitorsEnergy In CapacitorsWhat Is Impedance?Using ImpedanceSome Impedance Laws/Combinations
The capacitor is a widely used electrical component. It has several features that make it useful and important:
Capacitors are two-terminal electrical elements. Capacitors are essentially two conductors, usually conduction plates - but any two conductors - separated by an insulator - a dielectric - with conection wires connected to the two conducting plates.
Capacitors occur naturally. On printed circuit boards two wires running parallel to each other on opposite sides of the board form a capacitor. That's a capacitor that comes about inadvertently, and we would normally prefer that it not be there. But, it's there. It has electrical effects, and it will affect your circuit. You need to understand what it does.
At other times, you specifically want to use capacitors because of their frequency dependent behavior. There are lots of situations where we want to design for some specific frequency dependent behavior. Maybe you want to filter out some high frequency noise from a lower frequency signal. Maybe you want to filter out power supply frequencies in a signal running near a 60 Hz line. You're almost certainly going to use a circuit with a capacitor.
Sometimes you can use a capacitor to store energy. In a subway car, an insulator at a track switch may cut off power from the car for a few feet along the line. You might use a large capacitor to store energy to drive the subway car through the insulator in the power feed.
Capacitors are used for all these purposes, and more. In this chapter you're going to start learning about this important electrical component. Remember capacitors do the following and more.
You need to know what you should get from this lesson on capacitors. Here's the story.
Although this device first appeared in Leyden, a city in the Netherlands sometime before 1750. It was discovered by E. G. von Kleist and Pieter van Musschenbroek. Although it has been around for about 250 years, it has all of the elements of a modern capacitor, including:
If the top plate contains positive charge, and the bottom plate contains
negative charge, then there is a tendency for the charge to be bound on
the capacitor plates since the positive charge attracts the negative charge
(and thereby keeps the negative charge from flowing out of the capacitor)
and in turn, the negative charge tends to hold the positive charge in place.
Once charge gets on the plates of a capacitor, it will tend to stay there,
never moving unless there is a conductive path that it can take to flow
from one plate to the other.
There is also a standard circuit symbol
for a capacitor. The figure below shows a sketch of a physical capacitor,
the corresponding circuit symbol, and the relationship between Q and V.
Notice how the symbol for a capacitor captures the essence of the two plates
and the insulating dielectric between the plates.
Now, consider a capacitor that starts out with no charge on either plate. If the capacitor is connected to a circuit, then the same charge will flow into one plate as flows out from the other. The net result will be that the same amount of charge, but of opposite sign, will be on each plate of the capacitor. That is the usual situation, and we usually assume that if an amount of charge, Q, is on the positive plate then -Q is the amount of charge on the negative plate.
The essence of a capacitor is that it stores charge. Because they store charge they have the properties mentioned earlier - they store energy and they have frequency dependent behavior. When we examine charge storage in a capacitor we can understand other aspects of the behavior of capacitors.
In a capacitor charge can accumulate on the two plates. Normally charge of opposite polarity accumulates on the two plates, positive on one plate and negative on the other. It is possible for that charge to stay there. The positive charge on one plate attracts and holds the negative charge on the other plate. In that situation the charge can stay there for a long time.
That's it for this section. You now know pretty much what a capacitor is. What you need to learn yet is how the capacitor is used in a circuit - what it does when you use it. That's the topic of the next section. If you can learn that then you can begin to learn some of the things that you can do with a capacitor. Capacitors are a very interesting kind of component. Capacitors are one large reason why electrical engineers have to learn calculus, especially about derivatives. In the next section you'll learn how capacitors influence voltage and current.
There is a relationship between the charge on a capacitor and the voltage across the capacitor. The relationship is simple. For most dielectric/insulating materials, charge and voltage are linearly related.
Q = C Vwhere:
Q = C V
When V is measured in volts, and Q is measured in couloumbs, then C has the units of farads. Farads are really coulombs/volt.
The relationship, Q = C V, is the most important thing you can know about capacitance. There are other details you may need to know at times, like how the capacitance is constructed, but the way a capacitor behaves electrically is determined from this one basic relationship.
Shown to the right is a circuit that has a voltage source, V_{s}, a resistor, R, and a capacitor, C. If you want to know how this circuit works, you'll need to apply KCL and KVL to the circuit, and you'll need to know how voltage and current are related in the capacitor. We have a relationship between voltage and charge, and we need to work with it to get a voltage current relationship. We'll look at that in some detail in the next section.
The basic relationship in a capacitor is that the voltage is proportional to the charge on the "+" plate. However, we need to know how current and voltage are related. To derive that relationship you need to realize that the current flowing into the capacitor is the rate of charge flow into the capacitor. Here's the situation. We'll start with a capacitor with a time-varying voltage, v(t), defined across the capacitor, and a time-varying current, i(t), flowing into the capacitor. The current, i(t), flows into the "+" terminal taking the "+" terminal using the voltage polarity definition. Using this definition we have:
i_{c}(t) = C dv_{c}(t)/dt
This relationship is the fundamental relationship between current and voltage
in a capacitor. It is not a simple proportional relationship like we found
for a resistor. The derivative of voltage that appears in the expression
for current means that we have to deal with calculus and differential equations
here - whether we want to or not.
Q1 If the voltage across a capacitor is descreasing (and voltage and current are defined as above) is the current positive of negative?
We'll start by considering a time varying voltage across a capacitor. To
have something specific, let's say that we have a 4.7mf
capacitor, and that the voltage across the capacitor is the voltage time
function shown below. That voltage rises from zero to ten volts in one
millisecond, then stays constant at ten volts. Before you go on try
to determine what the current through the capacitor looks like, then answer
these questions.
Q2. Is the current constant in the time interval from t = 0 to t = 10 msec?
Q3. Is the current constant in the time interval from t = 10 msec to the last time shown?
Storing energy is very important. You count on the energy stored in your gas tank if you drove a car to school or work today. That's an obvious case of energy storage. There are lots of other places where energy is stored. Many of them are not as obvious as the gas tank in a car. Here are a few.
Capacitors are often used to store energy.
i(t) = C dv(t)/dt
P(t) = i(t)v(t)
We start
with a capacitor with a sinusoidal voltage across it.
where:
v_{C}(t) = V_{max} sin(wt)Knowing the voltage across the capacitor allows us to calculate the current:
i_{C}(t) = C dv_{C}(t)/dt = wC V_{max} cos(wt) = I_{max} cos(wt)
where I_{max}
= wC
V_{max}
Comparing the expressions for the voltage and current we note the following.
Now, with these observations in hand, it is possible to see that there may be an algebraic way to express all of these facts and relationships. The method reduces to the following.
Example 1 - The Capacitor
In a capacitor with sinusoidal voltage and currents, we have:
where:
V = V_{max}/0^{o}Similarly, we can get a representation for the current. However, first note:
i_{C}(t) = wC V_{max} cos(wt) = I_{max} cos(wt) = I_{max} sin(wt + 90^{o})(Here you must excuse the mixing of radians and degrees in the argument of the sine. The only excuse is that everyone does it!) Anyhow, we have:
I = I_{max}/90^{o} = j I_{max} = jwC V_{max}Where j is the square root of -1.
Then we would write:
V/I = V_{max}/jwC V_{max} = 1/jwCand the quantity 1/jwC is called the impedance of the capacitor. In the next section we will apply that concept to a small circuit - one you should have seen before.
Before moving to the next section, a little reflection is in order. Here are some points to think about.
In the last section we began to talk about the concept of impedance. Let us do that a little more formally. We begin by defining terms.
A sinusoidally varying signal (v_{C}(t) = V_{max} sin(wt) for example) will be represented by a phasor, V, that incorporates the magnitude and phase angle of the signal as a magnitude and angle in a complex number. Examples include these taken from the last section. (Note that these phasors have nothing to do with any TV program about outer space.)
v_{C}(t) = V_{max} sin(wt)
is represented by a phasor V = V_{max}/0^{o}^{}
i_{C}(t) = I_{max} sin(wt + 90^{o})
is represented by a phasor I = I_{max}/90^{o}
v_{a}(t) = V_{A} sin(wt + f)
is represented by a phasor V_{a} = V_{A}/f
Next, we can use the relationships for voltage and current phasors to analyze a circuit. Here is the circuit.
Now, this circuit is really a frequency dependent voltage divider, and it is analyzed differently in another lesson. However, here we will use phasors. At the end of this analysis, you should compare how difficult it is using phasors to the method in the other lesson.
We start by noting that the current in the circuit - and there is only one current - has a phasor representation:
We will use the current phase as a reference, and measure all other phases from the current's phase. That's an arbitrary decision, but that's the way we will start.
Next we note that we can compute the voltage across the capacitor.
V_{C} = I/jwC
This expression relates the current phasor to the phasor that represents the voltage across the capacitor. The quantity 1/jwC is the impedance of the capacitor. In the last section we justified this relationship.
We can also compute the phasor for the voltage across the resistor.
V_{R} = IRThis looks amazingly like Ohm's law, and it is, in fact, Ohm's law, but it is in phasor form. For that matter, the relationship between voltage and current phasors in a capacitor - just above - may be considered a generalized form of Ohm's law!
Now, we can also apply Kirchhoff's Voltage Law (KVL) to compute the phasor for the input voltage.
V_{IN} = V_{R} + V_{C} = IR + I/jwC = I(R + 1/jwC)
You should note the similarities in what happens here and what happens when you have two resistors in series.
Consider a series circuit of a resistor and capacitor. The series impedance is:
Z = R + 1/jwC
That's the same as we showed just above. The impedance can be used to predict relationships between voltage and current. Assume that the voltage across the series connection is given by:
v_{Series}(t) = V_{max} cos(wt)
That corresponds to having a voltage phasor of:
V = V_{max}/0^{o}
V = I Z
For our particular impedance, we have:
V = I*(R + 1/jwC)
So, we can solve for the current phasor:
I = V / (R + 1/jwC)
Now, we know the voltage phasor and we know the impedance so we can compute the current phasor. Let us look at some particular values.
Assume: